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Our current working model of the atom is base on quantum mechanic that incorporate the idea of quantize energy level , the wave property of electron ,
Our current working model of the atom is base on quantum mechanic that incorporate the idea of quantize energy level , the wave property of electron , and the uncertainty associate with electron location and momentum . If we know their energy , which we do , then the best is is we can do is to calculate a probability distribution that describe the likelihood of where a specific electron might be find , if we were to look for it . If we were to find it , we is know would know next to nothing about its energy , which imply we would not know where it would be in the next moment . We is refer refer to these probability distribution by the anachronistic , misleading , and bohrian term orbital . Why misleading ? Because to a normal person , the term orbital is implies imply that the electron actually has a define and observable orbit , something that is simply impossible to know ( can you explain why ? )
Another common and often useful way to describe where the electron is in an atom is to talk about the electron probability density or electron density for short. In this terminology, electron density represents the probability of an electron being within a particular volume of space; the higher the probability the more likely it is to be in a particular region at a particular moment. Of course you can’t really tell if the electron is in that region at any particular moment because if you did you would have no idea of where the electron would be in the next moment.
Erwin Schrödinger (1887–1961) developed, and Max Born (1882–1970) extended, a mathematical description of the behavior of electrons in atoms. Schrödinger used the idea of electrons as waves and described each atom in an element by a mathematical wave function using the famous Schrödinger equation (\(H \Psi=E \Psi\)). We assume that you have absolutely no idea what either \(H \Psi\) or \(E \Psi\) are but don’t worry—you don’t really need to. The solutions to the Schrödinger equation are a set of equations (wave functions) that describe the energies and probabilities of finding electrons in a region of space. They can be described in terms of a set of quantum numbers; recall that Bohr’s model also invoked the idea of quantum numbers. One way to think about this is that almost every aspect of an electron within an atom or a molecule is quantized, which means that only defined values are allowed for its energy, probability distribution, orientation, and spin. It is far beyond the scope of this book to present the mathematical and physical basis for these calculations, so we won’t pretend to try. However, we can use the results of these calculations to provide a model for the arrangements of electrons in an atom using orbitals, which are mathematical descriptions of the probability of finding electrons in space and determining their energies. Another way of thinking about the electron energy levels is that they are the energies needed to remove that electron from the atom or to move an electron to a “higher” orbital. Conversely, this is the same amount of energy released when an electron moves from a higher energy to a lower energy orbital. Thinking back to spectroscopy, these energies are also related to the wavelengths of light that an atom will absorb or release. Let us take a look at some orbitals, their quantum numbers, energies, shapes, and how we can used them to explain atomic behavior.
J.J. Thompson’s studies (remember them?) suggested that all atoms contained electrons. We can use the same basic strategy in a more sophisticated way to begin to explore the organization of electrons in particular atoms. This approach involves measuring the amount of energy it takes to remove electrons from atoms. This is known as the element’s ionization energy which in turn relates directly back to the photoelectric effect.
All atoms is are are by definition electrically neutral , which mean they contain equal number of positively- and negatively – charge particle ( proton and electron ) . We is remove can not remove a proton from an atom without change the identity of the element because the number of proton is how we define element , but it is possible to add or remove an electron , leave the atom ’s nucleus unchanged . When an electron is remove or add to an atom the result is is is that the atom has a net charge . atom ( or molecule ) with a net charge are know as ion , and this process ( atom / molecule to ion ) is call ionization . A positively charge ion is results ( call a cation ) result when we remove an electron ; a negatively charge ion ( call an anion ) result when we add an electron . remember that this add or remove electron becomes part of , or is remove from , the atom ’s electron system .
Now consider the amount of energy require to remove an electron . clearly energy is require to move the electron away from the nucleus that attract it . We is perturbing are perturb a stable system that exist at a potential energy minimum – that is the attractive and repulsive force are equal at this point . We is predict might naively predict that the energy require to move an electron away from an atom will be the same for each element . We is test can test this assumption experimentally by measure what is call the ionization potential . In such an experiment , we is determine would determine the amount of energy ( in kilojoule per mole of molecule ) require to remove an electron from an atom . let us consider the situation for hydrogen ( \(\mathrm{H}\ ) ) . We is write can write the ionization reaction as : \[\mathrm{H } \text { ( gas ) } + \text { energy } \rightarrow \mathrm{H}^{+ } \text { ( gas ) } + \mathrm{e}^{-}.\ ]
What we discover is that it take \(1312 \mathrm{~kJ}\ ) to remove a mole of electron from a mole of hydrogen atom . As we move to the next element , helium ( He ) with two electron , we is find find that the energy require to remove an electron from helium is \(2373 \mathrm{~kJ / mol}\ ) , which is almost twice that require to remove an electron from hydrogen !
Let us return to our model of the atom. Each electron in an atom is attracted to all the protons, which are located in essentially the same place, the nucleus, and at the same time the electrons repel each other. The potential energy of the system is modeled by an equation where the potential energy is proportional to the product of the charges divided by the distance between them. Therefore the energy to remove an electron from an atom should depend on the net positive charge on the nucleus that is attracting the electron and the electron’s average distance from the nucleus. Because it is more difficult to remove an electron from a helium atom than from a hydrogen atom, our tentative conclusion is that the electrons in helium must be attracted more strongly to the nucleus. In fact this makes sense: the helium nucleus contains two protons, and each electron is attracted by both protons, making them more difficult to remove. They are not attracted exactly twice as strongly because there are also some repulsive forces between the two electrons.
The size of an atom depends on the size of its electron cloud, which depends on the balance between the attractions between the protons and electrons, making it smaller, and the repulsions between electrons, which makes the electron cloud larger. The system is most stable when the repulsions balance the attractions, giving the lowest potential energy. If the electrons in helium are attracted more strongly to the nucleus, we might predict that the size of the helium atom would be smaller than that of hydrogen. There are several different ways to measure the size of an atom and they do indeed indicate that helium is smaller than hydrogen. Here we have yet another counterintuitive idea: apparently, as atoms get heavier (more protons and neutrons), their volume gets smaller!
Given that
Let us see if this trend continues as we move to the next heaviest element, lithium (\(\mathrm{Li}\)). Its ionization energy is \(520 \mathrm{~kJ/mol}\). Oh, no! This is much lower than either hydrogen (\(1312 \mathrm{~kJ/mol}\)) or helium (\(2373 \mathrm{~kJ/mol}\)). So what do we conclude? First, it is much easier (that is, requires less energy) to remove an electron from \(\mathrm{Li}\) than from either \(\mathrm{H}\) or \(\mathrm{He}\). This means that the most easily removed electron in \(\mathrm{Li}\) is somehow different than are the most easily removed electrons of either \(\mathrm{H}\) or \(\mathrm{He}\). Following our previous logic we deduce that the “most easily removable” electron in \(\mathrm{Li}\) must be further away (most of the time) from the nucleus, which means we would predict that a \(\mathrm{Li}\) atom has a larger radius than either \(\mathrm{H}\) or \(\mathrm{He}\) atoms. So what do we predict for the next element, beryllium (\(\mathrm{Be}\))? We might guess that it is smaller than lithium and has a larger ionization energy because the electrons are attracted more strongly by the four positive charges in the nucleus. Again, this is the case. The ionization energy of \(\mathrm{Be}\) is \(899 \mathrm{~kJ/mol}\), larger than \(\mathrm{Li}\), but much smaller than that of either \(\mathrm{H}\) or \(\mathrm{He}\). Following this trend the atomic radius of \(\mathrm{Be}\) is smaller than \(\mathrm{Li}\) but larger than \(\mathrm{H}\) or \(\mathrm{He}\). We could continue this way, empirically measuring ionization energies for each element (see figure), but how do we make sense of the pattern observed, with its irregular repeating character that implies complications to a simple model of atomic structure?
question to Answer
question to Ponder